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y^2-6y=39
We move all terms to the left:
y^2-6y-(39)=0
a = 1; b = -6; c = -39;
Δ = b2-4ac
Δ = -62-4·1·(-39)
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-8\sqrt{3}}{2*1}=\frac{6-8\sqrt{3}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+8\sqrt{3}}{2*1}=\frac{6+8\sqrt{3}}{2} $
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